WebThis video includes proof of converse of basic proportionality theorem (theorem 6.2).If you like our work, then you can donate us :-)Google Pay (G- Pay) : 89... WebDec 17, 2024 · In this case, A D A B − A D = A E A C − A E must be true for basic proportionality theorem to hold true. LHS = 5 10 − 5 = 1. RHS = 6 12 − 6 = 1. Hence, …
Converse Of BPT/THALES THEOREM Short Trick Chapter 6 …
WebHey!Thales Theorem is a nightmare for some students but in this video, we are going to learn it in a completely different way or should I say in a Dear Sir's... Let us now state the Basic Proportionality Theorem which is as follows: If a line is drawn parallel to one side of a triangle intersecting the other two sides in distinct points, then the other two sides are divided in the same ratio. See more Let us now try to prove the basic proportionality theorem statement Consider a triangle ΔABC, as shown in the given figure. In this … See more According to this theorem, if a line divides any two sides of a triangle in the same ratio, then the line is parallel to the third side. See more In a ∆ABC, sides AB and AC are intersected by a line at D and E respectively, which is parallel to side BC. Then prove that AD/AB = AE/AC. See more homewood suites schenectady new york
Basic Proportionality Theorem Thales Theorem
WebConverse of Basic proportionality theorem (BPT): According to this theorem, if a line divides any two sides of a triangle in the same ratio, then the line is parallel to the … WebMar 23, 2024 · Given: Δ ABC and a line DE intersecting AB at D and AC at E, such that "AD" /"DB" = "AE" /"EC" To Prove: DE ∥ BC Construction: Draw DE’ parallel to BC. Proof: Since DE’ ∥ BC , By Theorem 6.1 :If a line is … WebMar 30, 2024 · Proof: Given 𝐴𝐵/𝐷𝐸 = 𝐶𝐴/𝐷𝐹 And DP = AB, DQ = AC 𝐷𝑃/𝐷𝐸 = 𝐷𝑄/𝐷𝐹 𝐷𝐸/𝐷𝑃 = 𝐷𝐹/𝐷𝑄 Subtracting 1 on both sides 𝐷𝐸/𝐷𝑃 – 1 = 𝐷𝐹/𝐷𝑄 – 1 (𝐷𝐸 − 𝐷𝑃)/𝐷𝑃 = (𝐷𝐹 − 𝐷𝑄)/𝐷𝑄 𝑃𝐸/𝐷𝑃 = 𝑄𝐹/𝐷𝑄 𝐷𝑃/𝑃𝐸 = 𝐷𝑄/𝑄𝐹 Using Theorem 6.2 : If a line divides any two sides of a triangle in the same … historia6a